Question

If $\sqrt{3}$tan θ = 1 and θ is acute, find the value of sin 3θ + cos 2θ.

Answer 1

Step-by-step explanation:

$\sqrt{3} \tan(a) = 1 \\ \\ \tan(a) = \frac{1}{ \sqrt{3} } \\ \\ a = 30 \\ \\ \sin(3a) + \cos(2a) \\ \\ \sin(3(30) ) + \cos(2(30) ) \\ \\ \sin(90) + \cos(60) \\ \\ 1 + \frac{1}{2} = \frac{3}{2}$

Here's The Answer My Friend.....

Answer 2

Answer:

root 3tan Q =1.

tanQ= 1/root 3 .

tanQ=30°

Q=30°

So, the value of sin 3 Q = (3)30=90 =1

cos 2 Q = 2× 30 = 1,/2

so, according to the question: -->

1+1/2=3/2.

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