Question

If $\sqrt{64}$= 9, what is the value of 6$\pi$×

Answer 1

Step-by-step explanation:

The principal square root of

64

is:

√

64

=

8

The other (non-principal) square root is:

−

√

64

=

−

8

Explanation:

64

has two square roots, namely

8

and

−

8

, since:

8

2

=

(

−

8

)

2

=

64

When we say "the square root", what is usually intended is "the principal square root", which in the case of the Real square root of a positive number is the positive one.

Any non-zero number

n

has two square roots. In order to distinguish between them, we call one the "principal" square root, which in the case of

n

>

0

means the positive one

Answer 2

Answer:

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Step-by-step explanation:

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