Question

If
$\sqrt{?}$
1 and 2 are vertically opposite angles
and 1 = 7x -15° and 2 = 2x + 55°,
find the value of x.
​

Answer 1

$\huge\underline{\underline{\orange{\textbf{Solution : -}}}}$

• one angle is 7x - 15 °
• other one is 2x + 55 °

As we know that vertically opposite angles are equal to each other.

So,

Angle 1 = Angle 2

• We have to find the Value of x

So,

›› 7x - 15 = 2x + 55

›› 7x - 2x = 55 + 15

›› 5x = 70

›› x = 70/5

›› x = 14

hence

• Value of x is 14

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Answer 2

Aɴsᴡᴇʀ :

>> Value of x is 14°

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Given :

» Two angles that are vertically opposite angles

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀•⠀7x - 15°

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀•⠀2x + 55°

To Find :

» Value of x

Solution :

• ᖇᗴᗰᗴᗰᗷᗴᖇ : Vertically opposite angles are equal .

• So here both angles are equal and hence can be equated .

» $\sf 7x\:-\:15°\:=\:2x\:+\:55°$

» $\sf 7x\:-\:2x\:=\:55\:+\:15$

» $\sf 5x\:=\:70$

» $\sf x\:=\: \dfrac{70}{5}$

» x = 14°

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