if
![\sqrt{x} +1 \div \sqrt{x} = \sqrt{3} \sqrt{x} +1 \div \sqrt{x} = \sqrt{3}](https://tex.z-dn.net/?f=+%5Csqrt%7Bx%7D++%2B1+%5Cdiv++%5Csqrt%7Bx%7D++%3D++%5Csqrt%7B3%7D+)
then find the value of x²+1/16x²
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that's heckle3renew Danielle yellow relatives Janaଣଣଦଣବଦୂଵସଛୂ
pawan15032000:
ye kya hai??
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