Question

if
$\sqrt{x } + \sqrt{y } = 5find \: dy \div dx$
​

Answer 1

Answer:

Please refer to the image

Step-by-step explanation:

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Answer 2

Answer:

$\sqrt{x} + \sqrt{y} = 5 \\ \\ \frac{1}{2 \sqrt{x} } + \frac{1}{2 \sqrt{y} } ( \frac{dy}{dx} ) = 0 \\ \\ \frac{1}{2 \sqrt{x} } = - \frac{1}{2 \sqrt{y} } ( \frac{dy}{dx} ) \\ \\ \frac{ \sqrt{y} }{ \sqrt{x} } = - \frac{dy}{dx} \\ \\ so \: \: \: \frac{dy}{dx} = - \sqrt{ \frac{y}{x} }$