Question

If $\sum \limits^{5}_{n=1}\frac{1}{n(n+1)(n+2)(n+3)}=\frac{k}{3}$, then k is equal to
(a) $\frac{1}{6}$
(b) $\frac{17}{105}$
(c) $\frac{55}{336}$
(d) $\frac{19}{112}$

Answer 1

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