Math, asked by vgaddalayp6t0xb, 4 months ago

If \theta is the angle between the circles passing through \left(\lambda,2\lambda\right),(2\lambda,\lambda) and touching x-axis, then the locus of the point from which pair of tangents are drawn to the circle x^2+y^2-2x-2y-7=0 which includes the angle \theta is

Answers

Answered by balasupramanisp90
0

Answer:

The equations of the circles are:

x

2

+y

2

−2λx−2y−7=0

Hence, g=−λ,f=−1,c=−7 ....(1)

3x

2

+3y

2

−8x+29y=0

Hence, g

=−

3

4

,f

=

6

29

,c

=0 ....(2)

Since, they are given to be orthogonal circles, we have

2gg

+2ff

=c+c

2(−λ)(

3

−4

)+2(−1)(

6

29

)=−7

3

3

29

=−7

⇒8λ−29=−21

⇒8λ=8

⇒ λ=1

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