Question

if,
$\tt cosec\: \theta - sin\:\theta=a^3$
and,
$\tt sec\: \theta - cos\: \theta =b^3$
then prove that,
$\tt a^2b^2(a^2+b^2)=1$
​

Answer 1

Step-by-step explanation:

your answer hope it helps :-)

Answer 2

Step-by-step explanation:

refer to the attachment