if
![x = 1 x = 1](https://tex.z-dn.net/?f=x+%3D+1)
find the value of
![2 {x}^{2} - 7 {x}^{2} + 3x 2 {x}^{2} - 7 {x}^{2} + 3x](https://tex.z-dn.net/?f=2+%7Bx%7D%5E%7B2%7D++-+7+%7Bx%7D%5E%7B2%7D++%2B+3x)
Answers
Answered by
4
Answer:
Given,
Value of 'x' = 1
To Find :-
Solution:-
Value of 'x' = 1
=
Substituting value of 'x' :-
= - 5(1) + 3
= - 5 + 3
= 3 - 5
= - 2.
, When x = 1
Answered by
0
Answer:
-2
Step-by-step explanation:
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