Question

if
$x^{2} + 1 = 0$
then find the value of x​

Answer 1

$heya \\ \\ \\ x {}^{2} + 1 = 0 \\ \\ \\ \\ x {}^{2} = - 1 \\ \\ \\ \\ x = \sqrt{ - 1} \: \: \: \: \: \: \: or \: \: \: \: \: x = - \sqrt{ - 1} \\ \\ \\ \\ x = i \: \: \: \: \: or \: \: \: \: x = - i \\ \\ \\ \\ where \: \: i \: is \: iota \:$