Question

if
$x ^{2} + 1 \div x^{2} = 18find \: the \: value \: of \: x + 1 \div xandx - 1 \div x$
​

Answer 1

Answer:

2√(5) and 4

Step-by-step explanation:

x²+(1/x²)=18

(x+1/x)²=x²+1/x²+2

(x+1/x)²=18+2

x+1/x=√(20)=2√(5)

similarly

(x-1/x)²=x²+1/x²-2

(x-1/x)²=18-2

x-1/x=√(16)=4

hope it helps u