Math, asked by amishasoni077, 1 month ago

if
x {}^{2}  + 1 \div x  = 7 then \: find \: the \: value \: of \: x + 1 \div x
in given quation number 2

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Answers

Answered by xyz78455
63

Answer:

3 or -3

Step-by-step explanation:

=x^2+1/x^2=7

=(x+1/x)^2=x^2+1/x^2+2(x)(1/x)

=7+2

=9

3 or -3

Answered by amansharma264
48

EXPLANATION.

⇒ x² + 1/x² = 7.

As we know that,

⇒ (x + 1/x)² = x² + 1/x² + 2(x)(1/x).

⇒ (x + 1/x)² = x² + 1/x² + 2.

Put the value of x² + 1/x² = 7 in equation, we get.

⇒ (x + 1/x)² = 7 + 2.

⇒ (x + 1/x)² = 9.

⇒ (x + 1/x) = √9.

⇒ (x + 1/x) = 3.

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