Math, asked by seemasssingh4p893y4, 1 year ago

if
 {x}^{2}  +  \frac{1}{ {x}^{2} }  = 2 \\  \\  \\ so \: find \: the \: value \: of \\  \\  \\  \sqrt{x}  +  \frac{1}{ \sqrt{x} }
plz.... it's very urgent​

Answers

Answered by Anonymous
4

Hii its tom85

(1/x + x)^2 = x^2 + 1/x^2 + 2

(1/x + x)^2 = 4

(1/x + x)= + 2 and -2

(1/sqrt x + sqrt x)^2 = 1/x + x + 2

(1/sqrt x + sqrt x)^2 = 4

(1/sqrt x + sqrtx)=+2 , -2

__________/\____________☺️

hope it may helps you dude

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