If
find the value of
Vickypanjiyar:
.....
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1/x = 1/(2+√3)
= 4-3)/(2+√3)
= (2-√3)( √3+ 2)/(2+√3)
= 2-√3
x^2 + 1/x^2
( x+ 1/x)^2 - 2
( 2+ √3 + 2-√3)^2 -2
(4)^2 -2
16-2
14
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