Question

if
${x}^{2} - x - 42 = (x + k)(x + 6)$
then find the value of k ​

Answer 1

Answer:

X^2-x-42=(x+k)(x+6)

x^2-7x+6x-42=(x+k) (x+6)

(x+6)(x-7)=x+k(x+6)

X-7=x+k

K=-7 ans

Answer 2

Step-by-step explanation:

X^2-X-42=(x+k)(x+6)

X^2-7x+6x-42=(x+k)(x+6)

X(x-7)+6(x-7)=(x+k)(x+6)

(x+6)(x-7)=(x+k)(x+6)

(x-7)=(x+k)

K= - 7

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