Question

If $x^{3}-6x^{2} +ax+b$ is exactly divisible by $x^{2} -3x+2$, then 12a+22b=?

Answer 1

(2 - b)b = 48

2b -b^2= 48

now we have a quadratic equation :-

b^2 - 2b - 48=0

also, an multiplication the product will be -48

this will be in the

b^2 -8b +6b -48 =0

now by factorizing we have :-

b(b - 8) + 6(b - 8) = 0

(b+6)(b-8) = 0

b+6 = 0

b= -6

b - 8= 0

b=8

so the value of b can be 8 or -6

substituing the value of be in equation (i) we have :-

a + b = 2

a + 8 = 2

a = 2–8

a = -6

Answer 2

Answer:

The answer for this sum is a=-6