Question

if $x = 3 + \sqrt{8}$then the value of$( {x}^{2} + 1 \div {x}^{2} )$is​

Answer 1

Answer:

Which is greater than 4? (a) 5, ...

Which is the smallest? (a) -1, ...

Combine terms: 12a + 26b -4b – 16a. (a) 4a + 22b, ...

Simplify: (4 – 5) – (13 – 18 + 2). (a) -1, ...

What is |-26|? (a) -26, ...

Multiply: (x – 4)(x + 5) (a) x2 + 5x - 20, ...

Factor: 5x2 – 15x – 20. (a) 5(x-4)(x+1), ...

Factor: 3y(x – 3) -2(x – 3).

Answer 2

x=3+8–√…(1)x=3+8…(1)

⇒1x=3−8√(3)2−(8√)2⇒1x=3−8(3)2−(8)2

⇒1x=3−8–√….(2)⇒1x=3−8….(2)

Now adding (1) & (2) we get…

x+1x=(3+8–√)+(3−8–√)x+1x=(3+8)+(3−8)

⇒x+1x=6⇒x+1x=6

Now,

x2+1x2x2+1x2

=(x+1x)2–2.x1x=(x+1x)2–2.x1x

=62–2=62–2