Question

if
$x = 3$
is one root of the quadratic equation
$x {}^{2} - 2kx - 6 = 0$
, then find the value of
$k$

Answer 1

$\bold{Answer :}$

The given equation is

x² - 2kx - 6 =0 ...(i)

Since x = 3 is a root of (i) no. equation,

(3)² - 2k (3) - 6 = 0

or, 9 - 6k - 6 = 0

or, 6k = 3

or, k = 3/6

or, k = 1/2

Therefore, the value of k is 1/2

#$\bold{MarkAsBrainliest}$

Answer 2

Heya !!




X = 3




P ( X ) = X² - 2KX - 6



P (3) = (3)² - 2K × 3 - 6




=> 9 - 6K - 6 = 0




=> -6K + 3 = 0




=> K = 3/6


=> K = 1/2.