Question

If
$x = a \: sec \theta \:$
and
$y = b \: tan \theta \:$
Then find
$\frac{dy}{dx}$

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Answer 1

Answer:

$x = sec \alpha \\ y = tan \alpha \\ x = sec \alpha \\ dx = sec \alpha tan \alpha \\ y = tan \alpha$

$dy = sec {}^{2} \alpha \\ dy \div dx = sec \alpha tan \alpha \div sec {}^{2} \alpha \\ = > tan \alpha \div sec \alpha$

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Answer 2

Hi !!

Thanks for posting a beautiful question !

given , X = asec¢ _____(1)

and , y = btan¢ ______(2)

differentiating (1) with respect to d¢

dx/d¢ = asec¢* tan ¢

differentiating (2)with respect to d¢

dy/d¢ = bsec²¢ ______(2)

Now, dividing (2) to (1) we get ,

dy/dx = bsec²¢/asec¢* tan¢

dy/dx = b sec¢/atan¢

dy/dx = b/a sin¢ Answer

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Hope it's helpful

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