Question

if
$x \: \frac{ - 1}{2}$
$y\frac{ - 1}{3}$
then show that (x-y )is not equal to (y-x)
​

Answer 1

Answer:

$x = \frac{ - 1}{2} \: and \: y = \frac{ - 1}{3}$

$x - y = \frac{ - 1}{2} - \frac{ - 1}{3}$

LCM = 6

$\frac{ -3 }{6} - \frac{ - 2}{6} = \frac{ -3 }{6} + \frac{2}{6} = \frac{ - 1}{6}$

$y - x = \frac{ -1}{3} - \frac{ - 1}{2}$

LCM = 6

$\frac{ - 2}{6} - \frac{ - 3}{6} = \frac{ - 2}{6} + \frac{ 3}{6} = \frac{1}{6}$

$x - y = \frac{ - 1}{6}$

$y - x = \frac{1}{6}$

Which are ≠

Hence Proved

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