If
![(x + \frac{1}{3} \: \: \: \frac{y}{3} - 1) = ( \frac{1}{2} \: \: \frac{3}{2} ) \: find \: x \: and \: \: y (x + \frac{1}{3} \: \: \: \frac{y}{3} - 1) = ( \frac{1}{2} \: \: \frac{3}{2} ) \: find \: x \: and \: \: y](https://tex.z-dn.net/?f=%28x+%2B++%5Cfrac%7B1%7D%7B3%7D++++%5C%3A++%5C%3A++%5C%3A++%5Cfrac%7By%7D%7B3%7D++-+1%29+%3D+%28+%5Cfrac%7B1%7D%7B2%7D++%5C%3A++%5C%3A++%5Cfrac%7B3%7D%7B2%7D+%29+%5C%3A+find+%5C%3A+x+%5C%3A+and+%5C%3A+%5C%3A+y)
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Answer:
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Step-by-step explanation:
1/6=x
sh JC at hey if de the set
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