Math, asked by jpranavesh01, 1 month ago

if
x  -  \frac{1}{x}  = 2 \sqrt{3}
find the value of
 {x}^{3}  -  \frac{1}{ {x}^{3} }

Answers

Answered by sandy1816
1

x -  \frac{1}{x}  = 2 \sqrt{3}  \\  \\  {x}^{3}  -  \frac{1}{ {x}^{3} }  = ( {x -  \frac{1}{x} })^{3}   + 3(x -  \frac{1}{x} ) \\  {x}^{3}  -  \frac{1}{ {x}^{3} }  = ( {2 \sqrt{3} })^{3}  + 3 \times 2 \sqrt{3}  \\  = 24 \sqrt{3}  + 6 \sqrt{3}  \\  = 30 \sqrt{3}

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