Question

if
$x - \frac{1}{x}= 3$
find value of
${x}^{2} + \frac{1}{ {x}^{2} }$
​

Answer 1

$Given, \: x - \frac{1}{x} = 3 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = ( {x - \frac{1}{x}) }^{2} + 2x. \frac{1}{x} \\ \\ = {3}^{2} + 2 \\ \\ = 9 + 2 \\ \\ = 11$

I hope this helps.

Answer 2

Answer:

⭐ refer to the attachment ⭐

hope it helps uH ✔