If

Then find :-
(I)

(II)

(Tell the answer only if you know because I don't want it to be wrong)
(Give me the full solution not only the answer)
(Best answer will be marked as Brainliest)
(Answer all questions)
(Stupid Answers will be reported)
Answers
Answered by
1
(x-1/x)^2=x^2+1/x^2 -2x×1/x
5^2=x^2+1/x^2 -2
25+2=x^2+1/x^2
x^2+1/x^2=27
is your answer
5^2=x^2+1/x^2 -2
25+2=x^2+1/x^2
x^2+1/x^2=27
is your answer
Jatin0001:
there are two parts
Answered by
7
Hey !!!
x - 1/x = 5
•°• ( a - b ) ² = a² + b - 2ab
similarly
(x - 1/x )² = x² + 1/x² - 2x×1/x
5² = x² + 1/x² -2
25 + 2 = x² + 1/x²
x² + 1/x² = 27 -----1) 1st Answer ✔
________________________
now , 1/x⁴ + 1/x⁴
(1/x²)² + (1/x²)² can i write ?
hence, similarly
hence, a² + b² = ( a + b) ² - 2ab
since,
x⁴ + 1/x⁴ = ( x² + 1/x² ) ² - 2x² ×1/x²
x⁴ + 1/x⁴ = 27² - 2
x⁴ + 1/x⁴ = 729 - 2 ----[from 1st equation ]
x⁴ + 1/x⁴ = 727Answer
_________________________
Hope it helps you !!!
@Rajukumar111
x - 1/x = 5
•°• ( a - b ) ² = a² + b - 2ab
similarly
(x - 1/x )² = x² + 1/x² - 2x×1/x
5² = x² + 1/x² -2
25 + 2 = x² + 1/x²
x² + 1/x² = 27 -----1) 1st Answer ✔
________________________
now , 1/x⁴ + 1/x⁴
(1/x²)² + (1/x²)² can i write ?
hence, similarly
hence, a² + b² = ( a + b) ² - 2ab
since,
x⁴ + 1/x⁴ = ( x² + 1/x² ) ² - 2x² ×1/x²
x⁴ + 1/x⁴ = 27² - 2
x⁴ + 1/x⁴ = 729 - 2 ----[from 1st equation ]
x⁴ + 1/x⁴ = 727Answer
_________________________
Hope it helps you !!!
@Rajukumar111
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