Question

If
$x + \frac{1}{x} = 5 \: \: \: then \: \: \: \: \: x {}^{3} + \frac{1}{x {}^{2} }$
$x + \frac{1}{x} = 4 \: \: then \: {x}^{4} + \frac{1}{x {}^{4} }$
$x + \frac{1}{x} = 3 \: \: then \: x {}^{6} + \frac{1}{x {}^{6} }$
$x {}^{3} - \frac{1}{x {}^{3} } = 14 \: \: then \: x - \frac{1}{x}$
$a + b + c = 9 \: \: and \: ab + bc + ca = 23 \: \: then \: {a}^{2} + b {}^{2} + c {}^{2}$
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Answer 1

Answer:

X+1/X= 4 then x^4+1/x^4= 194

X+1/X= 3 then x^6+1/x^6= 322