Question

If
$x + \frac{1}{x} = 8$
find the value of
$x {}^{2} + \frac{1}{x {}^{2} }$
​

Answer 1

Answer:

Step-by-step explanation:

Squaring both side

(x+1/x)^2=8^2

x^2+1/x^2+2=64

x^2+1/x^2=64-2

x^2+1/x^2=62