Question

if
$x - \frac{1}{x}$
then write the value of
$4x + \frac{1}{4}$

​

Answer 1

Answer:

$x - \frac{1}{x} = \frac{ {x}^{2} - 1}{x}$

$\frac{ {x}^{2} - 1 }{x} = 0$

${x}^{2} - 1 = (x + 1)(x - 1) \\ x = 1 \: \: \: \: x = - 1$

$4x + \frac{1}{4} = 4 \times 1 + \frac{1}{4} = \frac{16 + 1}{4} = \frac{17}{4}$

$4x + \frac{1}{4} = 4 \times - 1 + \frac{1}{4} = \frac{ - 16 + 1}{4} = \frac{ - 15}{4}$

that's is your answer