Question

If
$x > 0$
and
${x}^{2} + \frac{1}{x} = \frac{9}{2}$
and
$x + \frac{1}{ {x}^{2} } = \frac{9}{4}$

find the value of
${x}^{3} + \frac{1}{x}$
a)9/8
b)19/8
c)19/9
d)17/8​

Answer 1

$x > 0$

and

${x}^{2} + \frac{1}{x} = \frac{9}{2}$

and

$x + \frac{1}{ {x}^{2} } = \frac{9}{4}$

find the value of

${x}^{3} + \frac{1}{x}$ option,c)19/9