Question

If
${(x + y)}^{1 \div 3} + {(y + z)}^{1 \div 3} + {(z + x)}^{1 \div 3} = 0$
then
${x}^{3} + {y}^{3} + {z}^{3}$
can be expressed as:
a. 1/8 xyz
b.(x+y)(y+z)(z+x)
c.3/8 (x+y)(y+z)(z+x)
d.3xyz​

Answer 1

Answer:

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