Question

If
$x + y = 9$
and
$xy = 16$
Find the value of
$(x^2 + y^2$
Please guys help me


Yeh Mera Kal ka Homework hai please guys​

Answer 1

Answer:

49

Step-by-step explanation:

$x + y = 9 \\ = > {(x + y)}^{2} = {9}^{2} \\ = > {x}^{2} + {y}^{2} + 2xy = 81 \\ = > {x}^{2} + {y}^{2} + 2(16) = 81 \\ = > {x}^{2} + {y}^{2} + 32 = 81 \\ = > {x}^{2} + {y}^{2} = 81 - 32 \\ = > {x}^{2} + {y}^{2} = 49$

IDENTITY USED:

(a+b)² = a²+b²+2ab

HOPE IT HELPS :D