Question

If
$y = {tan }^{ - 1} \sqrt{ \frac{a \: cosx - b \: sinx}{b \: cosx + a \: sinx} }$
find dy/dx​

Answer 1

Step-by-step explanation:

$ques...y = tan {}^{ - 1} ( \frac{ \sqrt{a \: cosx - b \: sinx} }{b \: cosx + a \: sinx}$

$\frac{dy}{dx } = \frac{1}{1 + ( \frac{ \sqrt{a \: cosx - b \: sinx} }{b \: cosx + a \: sinx}) }$

$\frac{b \: cosx + a \: sinx}{b \: cosx + a \: sinx + a \: cosx \: - b \: sinx}$

$\frac{b \: cosx + a \: sinx \: }{b(cosx - sinx) + a( \: sinx + cosx)}$

Hope this may helps you!!

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