if the 10 th term of an AP is 52 and 17th term of an AP is 20 more than 13 th term find AP and find the sum of first 15 terms
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Heya ☺☺☺☺
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===>> given, a10 =52
a + 9d =52 ...........(1)
also, a17 = 20+a13
a + 16d =20+a+12d
16d-12d=20
4d=20
d = 5
putting the value of d in eq. (1), we get,
a + 9(5) =52
a +45 = 52
a = 7
hence, the required AP is 7,12,17,....
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