If the 10th term of a geometric progression is 9 and 4th term is 4, then its 7th term is
Answers
Step-by-step explanation:
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The terms of a G.P. are of form a, ar, ar2, ar3,....
ar9 = 9
So, r9 = 9/a -----(1)
ar3 = 4 ----- (2)
Cubing both sides of (2), we get,
a3r9 = 64
putting value of r9 in this, we get,
a3 X 9/a = 64
9a2 = 64
a2 = 64/9
a = 8/3
Putting value of a = 8/3 in (2)
8/3 X r3 = 4
r3 = 12/8
Now, 7th term = ar6
= 8/3 X (r3)2
= 8/3 X 144/64
= 6
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Answer:
6
Step-by-step explanation:
The terms of a G.P. are of form a, ar, ar2, ar3,....
ar9 = 9
So, r9 = 9/a -----(1)
ar3 = 4 ----- (2)
Cubing both sides of (2), we get,
a3r9 = 64
putting value of r9 in this, we get,
a3 X 9/a = 64
9a2 = 64
a2 = 64/9
a = 8/3
Putting value of a = 8/3 in (2)
8/3 X r3 = 4
r3 = 12/8
Now, 7th term = ar6
= 8/3 X (r3)2
= 8/3 X 144/64
=6