If the 10th term of an A.P is 21 and the sum of first 10th term is 120 find the nth term
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Step-by-step explanation:
given, a10 =52
a + 9d =52 ...........(1)
also, a17 = 20+a13
a + 16d =20+a+12d
16d-12d=20
4d=20
d = 5
putting the value of d in eq. (1), we get,
a + 9(5) =52
a +45 = 52
a = 7
hence, the required AP is 7,12,17,........
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