If the 10th term of an A.P. is 21 and the sum of its first 10 term is 120‚ find its nth term.
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Answer:
1+n
Step-by-step explanation:
s₁₀ = 10 (a+l) / 2
120= 5 (a+21)
24= a+21
a = 3
a₁₀ = a+(10 - 1)d
21 = 3+9d
18=9d
d=2
aₙ= a+ (n-1)d
= 3+(n-1)2
= 3-2+n
= 1+n
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