Question

if the 10th term of an AP is 52 and 17th term is 20 more than its 13th term , find AP​

Answer 1

In the given AP , let the first term be a and common difference be d .

Then,

An = a + ( n -1)d , where n is any natural number .

Now, we have

A10 = a + ( 10-1 )d

$\implies$a + 9d ------------(1)

A13 = a + ( 13-1 )d = a + 12d --------------(2)

A17 = a + ( 17-1 )d = a + 16d ---------------(3)

But, it is given that A17 = 20 + A13

$\implies$ a + 16d = 20 + a + 12d

$\implies$ 4d = 20

$\implies$ d = 5

on substituting d = 5 in (1), we get

a + 9 × 5 = 52

$\implies$a = 7

Thus, a = 7 and d = 5

The AP is

a = 7

a + d = 7 + 5 = 12

a + 2d = 7 + (5×2) = 17

$\implies$ AP = 7, 12, 17. . . . .

Answer 2

top answer is absolutely correct

Step-by-step explanation:

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