Question

If the 10th term of an Ap is 52 and 17th term is 20 more than its 13th term, find the AP.

Answer 1

Hey friend here is your answer

Given,

A10-----52
A+9D-----52------(1)

A17-----A13+20
A+16D---A+12D+20

A-A+16D-12D==20

4D=20
D=5---------(2)

Putting value of A in (1)

We have ,
A+45=52
A=52-45
A=7-------(3)

Thus we have the following AP

7,12,17........


Hope it helps you

Pls mark brainliest:-)

Answer 2

Answer:

AP=7,12,17,.....

Step-by-step explanation:

Formula of nth term pf AP = $a_n=a+(n-1)d$ --A

Substitute n = 10

$a_{10}=a+(10-1)d$

$a_{10}=a+9d$

Now we are given that  10th term of an Ap is 52

So, $52=a+9d$ ---B

Now substitute n 17 in A

$a_{17}=a+(17-1)d$

$a_{17}=a+16d$

Substitute n= 13

$a_{17}=a+(13-1)d$

$a_{17}=a+12d$

Now we are given that 17th term is 20 more than its 13th term

So, $a_{17}=a_{13}+20$

$a+16d=a+12d+20$

$16d-12d=20$

$4d=20$

d=5

So, common difference of AP is 5

Substitute the value of d in B to get value of A

$52=a+9(5)$

$52=a+45$

$7=a$

First term is 7

So, AP = 7,7+5,7+5+5,....

AP=7,12,17,.....