If the 10th term of an AP is seven
times the second term & 12th term
is 34.
Find the Progression A.P.
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0
Answer:
The ninth term of an AP is equal to seven times the second term and twelfth term exceeds five times the third term by 2. Find the first term and the common difference
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0
Answer:1,4,7...
Step-by-step explanation:an=a+(n-1)d
a10=a+9d
a2=a+d
a12= a+11d
But a12=34
a+11d=34...(2)
And, it is said that 10th term of an AP is seven times the second term
a+9d=7(a+d)
7a+7d=a+9d
6a-2d=0
3a-d=0...(1)×11
33a-11d=0...(3)
(2)+(3), we get
34a=34
a=1
putting this value in (3), we get
33=11d
d=3
The progression 1,4,7....
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