if the 10th term of AP is 15 and 15 term is 10 then the fourth term is
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Answered by
5
a10 =15
a+9d =15 -1
a15=10
a+14d =10 -2
subtractingeq1and2
a+9d=15
a+14d=10
we get -5d =5
d =-1
a+9d = 15
a+9×-1=15
a +(-9)=15
a=15+9=24
a4 = a+3d
= 24+3×-1
=24+(-3)
=21
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Answered by
1
15 th term = a+14d=10-----1
10 term =a+9d=15---------2
subtracting equation 1 and 2
d=-5
substituting d in equation 1
a+9×(-5)=10
a-45=10
a=55
we know that a is 55 and d is -5
so fourth term will be
4 th term = a+3d
55+3×(-5)
55-15
40
their fore fourth term is 40
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