If the 10th term of the ap is 52 and the17th term is 20 more than the 13th term , find the ap
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Let 'a' be the first term and 'd' be the common difference of the AP.
a10 = 52 and a17=20 a13
a+ 9d=52 and a+16d =20+a+12d
a+9d=52 and 16d=20+12d
a+9d=52 & d=5
a+5=52
a=47
So AP is a, a+d, a+2d.....I.e.
47,52,59......
a10 = 52 and a17=20 a13
a+ 9d=52 and a+16d =20+a+12d
a+9d=52 and 16d=20+12d
a+9d=52 & d=5
a+5=52
a=47
So AP is a, a+d, a+2d.....I.e.
47,52,59......
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