If the 11th and 13th terms of an A.P. are 35 and 41 respectively , then find its common
difference.
Answers
Answered by
1
Answer:
a+10d=34......(.1)
a+13d=41.........(2)
(2)-(1)
a+13d=41
-a-10d=-34
therefore , d=-7/3
Answered by
9
Answer: d=3
Explanation:
11th term of AP is
35 = a +10d. ------1
13th term of AP is
41 = a +12d ------2
Subtract (1) and (2)
41 - 35 = a +12d - a -10d
6 = 2d
d = 3
Similar questions