if the 11th term of a GP is 2048 and 16th term is 65536, find its 7th term.
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Answer:
hy probably this gives uh an idea
Step-by-step explanation:
solution : let first 11 terms in geometric progression are ; a/r^5, a/r^4, a/r^3, a/r^2, a/r, a , ar, ar^2, a^3, ar^4, ar^5.
a/c to question,
product of 11 terms = 2048
⇒ (a/r^5 × a/r^4 × a/r^3 × a/r^2 × a/r × a × ar × ar^2 × ar^3 × ar^4 × ar^5) = 2048
⇒ a¹¹ = 2048 = (2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 )
⇒a¹¹ = 2¹¹
⇒ a = 2
now see series here 6th term is a.
so, 6th term of given geometric progression , a = 2.
and 7th term is of the given progression is just substitute the value
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