if the 11th term of an ap is 44 and 16th term is 19, find the 20th term and the ap.
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tn=a+(n-1)d
t44 = a + (44-1)d
=> t44 = a + 43d = 44 -------------------------(1)
t16 = a +(16-1)d
=> t16 = a + 15d = 19 ---------------------------(2)
Subtract (1) - (2)
=> a + 43d - a - 15d = 44-19
=> 43d - 15d =25
=>28d = 25
=> d => 25/28
substituting d in equation (2)
=> a + 15(25/28) = 19
=> a = 19 - 15(0.8929)
=> a = 19 - 13.39
=> a = 5.607
t20 = 5.607 + (19)25/28
t20 = 5.607 + 16.964
t20 = 22.571
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