If the 12th term of an ap is -13 and the sum of first four terms is 24 what is the sum of first 10 terms.?
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Answer:
The sum of first ten terms is 0.
Step-by-step explanation:
The 12th term of an AP is -13.
So,a+11d = -13
a= -13 - 11d
The sum of first four terms is 24.
So, 24= 4/2[2a+3d]
12 = 2a + 3d
12 = 2(-13-11d)+3d
12= -26 - 22d+3d
38 = -19d
d = -2
Put d value in a+11d = -13
So, a + 11(-2)= -13
a= -13+22
a = 9
a= 9 and d =-2
So,the sum of first ten terms is
S10 = 10/2[2(9)+(10-1)(-2)]
= 5(18-18)
= 0
The sum of first ten terms is 0.
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