Question

If the 15th of an AP is 59 and 11th of the same
Ap is 43 then its 150 th term is
​

Answer 1

Answer:

599

Step-by-step explanation:

Let the first term be "a"and common difference be "d"

15 th term = 59

a + (15 - 1) d = 59

a + 14d = 59  .......(1)

11 th term = 43

a + (11 - 1) d = 43

a + 10d = 43  .......(2)

From 1 and 2 we get,

d = 4 , a = 3

So, 150 th term is

   = 3 + (150 - 1) 4

   = 3 + 596

   = 599

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Answer 2

Step-by-step explanation:

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