If the 15th term of an A.P is 121 and 25th term is 201 ,then the 35th term of the A.Pis
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it was very open and the like of 2834
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281
Step-by-step explanation:
15th term = a + 14d = 121 - - - (1)
25th term = a + 24d = 201 - - - (2)
On subtracting (1) from (2)
=> 10d = 80
=> d = 8
Put the value of d in (1)
=> a + 14(8) = 121
=> a = 121 - 112
=> a = 9
Therefore 35 term of ap is
= 9 + (35 - 1) × 8
= 9 + 272
= 281
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