If the 17 term of an ap exceeds the 10 term By 7 find the common difference
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Let a be the first term and d be the common difference.
a17= a+16d
a10=a+9d
According to the given question,
a17 = a10 + 7
a+16d = a+9d+7
16d - 9d = 7
7d = 7
d = 1
So, The Common difference (d) = 1
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