Question

if the 17 th term of an ap exceeds its 10th term by 7, find the common difference of ap.​

Answer 1

Let a be the first term and d be the common difference of A.P.

17th term of A.P t17 = a + 16d.

10th term of A.P is t10 = a + 9d.

Given that 17th term of an A.P exceeds its 10th term by 7.

a + 16d = a + 9d + 7

7d = 7

∴ d = 1

Hope it helps you

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

Given, 17th term exceeds its 10th term by 7.

It means a17 = a10 + 7         ........eq(1)

Here, a17 is the 17th term and a10 is the 10th term of an AP.

Using formula an=a+(n−1)d,   to find nth term of arithmetic progression, we get

a17=a+(16)d      ..........eq (2)

a10=a+(9)d    .........eq(3)

Putting (2) and (3) in equation (1), we get

a+16d=a+9d+7

⇒7d=7

⇒d=7/7=1

I hope, this will help you.

Thank you______❤

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