if the 17 th term of AP exceeds it's 10 th term by 7 find the common different and a
Answers
Answered by
8
Answer:
a+16d-(a+9d)=7
=> a+16d-a-9d=7
=> 7d=7
=> d=1
hope it helps you....
Answered by
1
Answer:
Let a ne the first term and d be the common difference.
tn=a+(n-1) d....... (Formula)
t17=a+16d............. (1)
t10=a+9d.............. (2)
Therefore, From given condition,
a+16d=a+9d-7..... (3)
a-a+16d-9d=-7
7d=-7
d=-1
Therefore, substituting the value of d in (3)
a-16=a-9-7
a-16=a-16
therefore, a=0
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