If the 17th term of an A. P. Exceeds it's 10 to term by 7 find the common difference
Answers
Answered by
1
Answer:
Hola Friend..............
Let a be the first term and d be the common difference of A.P.
17th term of A.P t17 = a + 16d.
10th term of A.P is t10 = a + 9d.
Given that 17th term of an A.P exceeds its 10th term by 7.
a + 16d = a + 9d + 7
7d = 7
∴ d = 1
Answered by
1
Answer: a17=a10 +7
a17- a10 = 7
Similar questions